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Proof step 3 from proof discard-add2-lels-left (previous step)

0 < j ⊦ i < j0, j0 < i + j

User applied rule cut formula

And obtained the following new goals

Proof step 4:
0 < j, j0 + j < i + j ⊦ j0 < i + j, i < j0

Rule argument

fma: j0 + j < i + j

Additional information

Used simplifier rules: ⊦ i + j < i + i0 ↔ j < i0; (s)% ⊦ ¬ i < j → (j < i ↔ i ≠ j); (ss)%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2% ⊦ 0 < i → i1 < i1 + i; (s) Used formulas: j0 + j < i + j