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Proof step 4 from proof discard-add2-lels-left (previous step)

0 < j, j0 + j < i + j ⊦ j0 < i + j, i < j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
0 < j, j0 < i ⊦ j0 < i + j

Rule argument

Additional information

Used simplifier rules: ⊦ i < j → ¬ j < i; (s)%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2% ⊦ i + j < i + i0 ↔ j < i0; (s)