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Proof step 10 from proof div-eq-same-01 (previous step)

i / j = i ⊦ i = 0, j = 1, j = 0, j < 0 ∧ i < 0, 0 < j ∧ 0 ≤ i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
i / j = i ⊦ i = 0, j = 0, j = 1, j < 0 ∧ i < 0, 0 < j ∧ 0 < i

Rule argument

Additional information

Used simplifier rules: ⊦ i ≠ j → (i ≤ j ↔ i < j); (s)