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Proof step 11 from proof div-eq-same-01 (previous step)

i / j = i ⊦ i = 0, j = 0, j = 1, j < 0 ∧ i < 0, 0 < j ∧ 0 < i

User applied rule cut formula

And obtained the following new goals

Proof step 12:
i / j = i, 0 < j ⊦ i = 0, j = 1, j = 0, 0 < j ∧ 0 < i, j < 0 ∧ i < 0
Proof step 23:
i / j = i ⊦ i = 0, j = 1, j = 0, 0 < j, 0 < j ∧ 0 < i, j < 0 ∧ i < 0

Rule argument

fma: 0 < j

Additional information

Used formulas: 0 < j