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Proof step 23 from proof div-eq-same-01 (previous step)

i / j = i ⊦ i = 0, j = 1, j = 0, 0 < j, 0 < j ∧ 0 < i, j < 0 ∧ i < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 24:
i / j = i, 0 < i, j < 0 ⊦ j = 1

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs% ⊦ i < 0 ∧ 0 ≤ j → i < j; (s)% ⊦ i < j → ¬ j < i; (s)% ⊦ ¬ i < j → (i = j ↔ ¬ j < i); (ss)