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Proof step 17 from proof div-eq-zero-01 (previous step)

i < 0, 0 < abs(j) + i ⊦ i / j = 0, 0 = j

User applied rule cut formula

And obtained the following new goals

Proof step 18:
0 < abs(j) + i, i < 0, i < j ⊦ i / j = 0, 0 = j
Proof step 20:
0 < abs(j) + i, i < 0 ⊦ i / j = 0, 0 = j, i < j

Rule argument

fma: i < j

Additional information

Used formulas: i < j