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Proof step 16 from proof div-eq-zero-01 (previous step)

i < 0, 0 < abs(j) + i ⊦ i / j = 0, 0 = j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
i < 0, 0 < abs(j) + i ⊦ i / j = 0, 0 = j

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs