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Proof step 8 from proof div-eq-zero-01 (previous step)

i < 0 ⊦ i / j = 0 ↔ 0 < abs(j) + i, 0 = j

User applied rule case distinction

And obtained the following new goals

Proof step 9:
i / j = 0, i < 0 ⊦ 0 = j, 0 < abs(j) + i
Proof step 16:
i < 0, 0 < abs(j) + i ⊦ i / j = 0, 0 = j

Rule argument

pos: right 1

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