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Proof step 5 from proof div-le-pos (previous step)

i0 / j < i / j, 0 < j, i0 / j < j0, j0 ≤ i / j, i ≤ i0 ⊦ 0 < j ∧ 0 ≤ i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
i0 / j < j0, 0 < j, i0 / j < i / j, i < 0, i ≤ i0, j0 ≤ i / j ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs% ⊦ i ≤ j ↔ ¬ j < i; (ss)