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Proof step 6 from proof div-le-pos (previous step)

i0 / j < j0, 0 < j, i0 / j < i / j, i < 0, i ≤ i0, j0 ≤ i / j ⊦

User applied rule cut formula

And obtained the following new goals

Proof step 7:
i < 0, i0 / j < i / j, 0 < j, i0 / j < j0, j0 ≤ i / j, i ≤ i0 ⊦ j < 0

Rule argument

fma: j < 0

Additional information

Used simplifier rules: ⊦ i < j → ¬ j < i; (s) Used formulas: j < 0