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Proof step 17 from proof div-ls-mone (previous step)

i0 < 0, 0 < j + j0, j0 < 0, i0 < j + j0, j0 < j, i0 < j, 0 < j, i0 < ~1 ⊦ i0 = ~1, j * (2 + i0) + j0 ≤ 0, j < 0 ∧ j0 < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
i0 < ~1, 0 < j, i0 < j, j0 < j, i0 < j + j0, j0 < 0, 0 < j + j0, i0 < 0, 0 < j * (2 + i0) + j0 ⊦ i0 = ~1

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs% ⊦ i < j → ¬ j < i; (s)% ⊦ i ≤ j ↔ ¬ j < i; (ss)