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Proof step 18 from proof div-ls-mone (previous step)

i0 < ~1, 0 < j, i0 < j, j0 < j, i0 < j + j0, j0 < 0, 0 < j + j0, i0 < 0, 0 < j * (2 + i0) + j0 ⊦ i0 = ~1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 19:
⊦ i < 0 ∧ j < 0 → ¬ 0 < i + j
Proof step 20:
0 < j * (2 + i0) + j0, i0 < 0, 0 < j + j0, j0 < 0, i0 < j + j0, j0 < j, i0 < j, 0 < j, i0 < ~1 ⊦ i0 = ~1, j * (2 + i0) < 0 ∧ j0 < 0

Rule argument

spec: int-basic2 name: ls-zero seq: ⊦ i < 0 ∧ j < 0 → ¬ 0 < i + j subst: [j, i] → [j0, j * (2 + i0)] flags: <all paths>

Additional information

Used terms: j0, j * (2 + i0)