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Proof step 1 from proof div-nls-01 (conclusion)
⊦ ¬ i0 < abs(i) ∧ i ≤ 0 ∧ j < 0 → ¬ i0 < i / j
System applied rule normalize
And obtained the following new goals
Proof step 2
:
i0 < i / j, j < 0, i ≤ 0 ⊦ i0 < abs(i)
Rule argument
Additional information