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Proof step 2 from proof div-nls-01 (previous step)

i0 < i / j, j < 0, i ≤ 0 ⊦ i0 < abs(i)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i0 < i / j, j < 0, abs(i) < i / j, abs(i) ≤ i0, i ≤ 0 ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-04: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward) from specification int-abs%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs% ⊦ i < j ↔ ¬ j ≤ i; (ss)