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Proof step 16 from proof div-two-intro (previous step)

i0 * 2 = i1 + 1, i0 ≤ 0 ⊦ i1 / (j0 * 2) = i0 / j0, j0 = 0

User applied rule cut formula

And obtained the following new goals

Proof step 17:
i0 * 2 = i1 + 1, i1 = i0 * 2 - 1, i0 ≤ 0 ⊦ i1 / (j0 * 2) = i0 / j0, j0 = 0

Rule argument

fma: i1 = i0 * 2 - 1

Additional information

Used simplifier rules: ⊦ i - j = i0 ↔ i = i0 + j; (s) Used formulas: i1 = i0 * 2 - 1