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Proof step 17 from proof div-two-intro (previous step)

i0 * 2 = i1 + 1, i1 = i0 * 2 - 1, i0 ≤ 0 ⊦ i1 / (j0 * 2) = i0 / j0, j0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
i0 ≤ 0 ⊦ (i0 * 2 - 1) / (j0 * 2) = i0 / j0, j0 = 0

Rule argument

Additional information

Used simplifier rules: commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult% ⊦ 0 < i → (i * j = i * j0 ↔ j = j0); (s)%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2% ⊦ i + (j - i) = j; (s)