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Proof step 3 from proof div-two-intro (previous step)

j % 2 = 0 ⊦ i / j = (i / 2) / j / 2, j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
j ≠ 0 ⊦ i % j = 0 ↔ (∃ j0. i = j0 * j)
Proof step 5:
∃ j0. j = j0 * 2 ⊦ i / j = (i / 2) / j / 2, 2 = 0, j = 0

Rule argument

spec: <toplevel> name: modex seq: j ≠ 0 ⊦ i % j = 0 ↔ (∃ j0. i = j0 * j) subst: [j, i] → [2, j] flags: <all paths>

Additional information

Used terms: 2, j