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Proof step 5 from proof div-two-intro (previous step)

∃ j0. j = j0 * 2 ⊦ i / j = (i / 2) / j / 2, 2 = 0, j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
⊦ i / (j0 * 2) = (i / 2) / j0, j0 = 0

Rule argument

Additional information

Used simplifier rules: div-mult-03: j ≠ 0 ⊦ (i * j) / j = i;%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult% ⊦ 2 * i = 0 ↔ i = 0; (s)