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Proof step 10 from proof le-abs-numerator (previous step)

0 < i / j + i, i < 0, 0 ≤ i ∧ 0 < j → i / j * j ≤ i ⊦ j = 0

User applied rule cut formula

And obtained the following new goals

Proof step 11:
i < 0, 0 < i / j + i, j < 0, 0 ≤ i ∧ 0 < j → i / j * j ≤ i ⊦ j = 0
Proof step 18:
i < 0, 0 < i / j + i, 0 ≤ i ∧ 0 < j → i / j * j ≤ i ⊦ j = 0, j < 0

Rule argument

fma: j < 0

Additional information

Used formulas: j < 0