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Proof step 11 from proof le-abs-numerator (previous step)

i < 0, 0 < i / j + i, j < 0, 0 ≤ i ∧ 0 < j → i / j * j ≤ i ⊦ j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
0 < i / j + i, i < 0, j < 0 ⊦ j = 0

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs% ⊦ i < j → ¬ j < i; (s)