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Proof step 3 from proof mod-nls-02 (previous step)

i % j < i0, i0 < 0, 0 < i, i0 ≤ i, abs(j) = 1 ∨ abs(j) ≤ i ⊦ j = 0

User applied rule cut formula

And obtained the following new goals

Proof step 4:
0 < i, i0 < 0, i % j < i0, i % j < 0, i0 ≤ i, abs(j) = 1 ∨ abs(j) ≤ i ⊦ j = 0

Rule argument

fma: i % j < 0

Additional information

Used simplifier rules: ⊦ i < j ∧ ¬ i0 < j → ¬ i0 < i; (s) Used formulas: i % j < 0