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Proof step 4 from proof mod-nls-02 (previous step)

0 < i, i0 < 0, i % j < i0, i % j < 0, i0 ≤ i, abs(j) = 1 ∨ abs(j) ≤ i ⊦ j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ 0 ≤ i ∧ j ≠ 0 → ¬ i % j < 0

Rule argument

spec: <toplevel> name: mod-zero-06 seq: ⊦ 0 ≤ i ∧ j ≠ 0 → ¬ i % j < 0 subst: [j, i] → [j, i] flags: <all paths>

Additional information

Used simplifier rules: ⊦ i ≤ j ↔ ¬ j < i; (ss)% ⊦ i < j → ¬ j < i; (s) Used terms: j, i