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Proof step 1 from proof two-add-square-01 (conclusion)
⊦ 0 < i → ((i * (i - 1)) / 2 + i = (i * (i + 1)) / 2 ↔ true)
System applied rule normalize
And obtained the following new goals
Proof step 2
:
0 < i ⊦ (i * (i - 1)) / 2 + i = (i * (i + 1)) / 2 ↔ true
Rule argument
Additional information