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Proof step 2 from proof two-add-square-01 (previous step)

0 < i ⊦ (i * (i - 1)) / 2 + i = (i * (i + 1)) / 2 ↔ true

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: two-add-square seq: ⊦ 0 ≤ i → ((i * (i - 1)) / 2 + i = (i * (i + 1)) / 2 ↔ true) subst: [i] → [i] flags: <all paths>

Additional information

Used simplifier rules: ⊦ i ≤ j ↔ ¬ j < i; (ss)% ⊦ i < j → ¬ j < i; (s) Used terms: i