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Proof step 13 from proof gcd-one-eq (previous step)

j2 / gcd(i2, j2) = 1, 0 ≤ gcd(i2, j2) ⊦ gcd(i2, j2) = j2, j2 ≥ 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
j2 / gcd(i2, j2) = 1, j2 < 0, 0 ≤ gcd(i2, j2) ⊦ gcd(i2, j2) = j2

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 ∧ 0 ≤ j → i < j; (s)%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs% ⊦ i ≥ j ↔ ¬ i < j; (s)