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Proof step 5 from proof gcd-one-eq (previous step)

j2 / gcd(i2, j2) = 1, 0 ≤ gcd(i2, j2) ⊦ gcd(i2, j2) = j2

User applied rule cut formula

And obtained the following new goals

Proof step 6:
j2 / gcd(i2, j2) = 1, 0 ≤ gcd(i2, j2), j2 ≥ 0 ⊦ gcd(i2, j2) = j2
Proof step 13:
j2 / gcd(i2, j2) = 1, 0 ≤ gcd(i2, j2) ⊦ gcd(i2, j2) = j2, j2 ≥ 0

Rule argument

fma: j2 ≥ 0

Additional information

Used formulas: j2 ≥ 0