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Proof step 5 from proof gcd-prime (previous step)

0 < j, 1 < i, 0 < i, i < j, 1 < j, prime(j) ⊦ ∀ i1. ¬(i1 > 1 ∧ i1 | i ∧ i1 | j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
1 < j, i < j, 0 < i, 1 < i, 0 < j, 0 < i0, 1 < i0, prime(j), i0 | i, i0 | j ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-pos: ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward) from specification int-basic1% ⊦ i > j ↔ j < i; (s)