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Proof step 6 from proof gcd-prime (previous step)

1 < j, i < j, 0 < i, 1 < i, 0 < j, 0 < i0, 1 < i0, prime(j), i0 | i, i0 | j ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ prime(j) ↔ 2 ≤ j ∧ (∀ i. 1 < i ∧ i < j → ¬ i | j)
Proof step 8:
1 < i0, 0 < i0, 0 < j, 1 < i, 0 < i, i < j, 1 < j, i0 | j, i0 | i, 2 ≤ j, ∀ i. 1 < i ∧ i < j → ¬ i | j ⊦

Rule argument

spec: <toplevel> name: prime-def seq: ⊦ prime(j) ↔ 2 ≤ j ∧ (∀ i. 1 < i ∧ i < j → ¬ i | j) subst: [j] → [j] flags: <all paths>

Additional information

Used terms: j