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Proof step 65 from proof gcd-rec-sub-03 (previous step)

i0 < 0, i0 < i, 0 < i ⊦ gcd(abs(i), abs(i0 + i)) = gcd(i0 + i, i0), i = 0, i0 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 66:
⊦ gcd(i, j) = gcd(abs(i), abs(j))
Proof step 67:
0 < i, i0 < i, i0 < 0 ⊦ gcd(abs(i), abs(i0 + i)) = gcd(abs(i0 + i), abs(i0)), i = 0, i0 = 0

Rule argument

spec: <toplevel> name: gcd-abs-rew-02 seq: ⊦ gcd(i, j) = gcd(abs(i), abs(j)) subst: [j, i] → [i0, i0 + i] flags: <all paths>

Additional information

Used terms: i0, i0 + i