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Proof step 67 from proof gcd-rec-sub-03 (previous step)

0 < i, i0 < i, i0 < 0 ⊦ gcd(abs(i), abs(i0 + i)) = gcd(abs(i0 + i), abs(i0)), i = 0, i0 = 0

User applied rule cut formula

And obtained the following new goals

Proof step 68:
i0 < 0, i0 < i, 0 < i, abs(i0) < abs(i) ⊦ gcd(abs(i), abs(i0 + i)) = gcd(abs(i0 + i), abs(i0)), i = 0, i0 = 0
Proof step 80:
i0 < 0, i0 < i, 0 < i ⊦ gcd(abs(i), abs(i0 + i)) = gcd(abs(i0 + i), abs(i0)), i = 0, i0 = 0, abs(i0) < abs(i)

Rule argument

fma: abs(i0) < abs(i)

Additional information

Used formulas: abs(i0) < abs(i)