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Proof step 80 from proof gcd-rec-sub-03 (previous step)

i0 < 0, i0 < i, 0 < i ⊦ gcd(abs(i), abs(i0 + i)) = gcd(abs(i0 + i), abs(i0)), i = 0, i0 = 0, abs(i0) < abs(i)

User applied rule cut formula

And obtained the following new goals

Rule argument

fma: abs(i0 + i) = abs(i0) - abs(i)

Additional information

Used simplifier rules: gcd-neg: ⊦ gcd(~ i, j) = gcd(i, j);%gcd-com: ⊦ gcd(i, j) = gcd(j, i);% ⊦ 0 < j → abs(j) = j; (s)% ⊦ i < 0 → abs(i) = ~ i; (s)% ⊦ ~ i - j = ~(i + j); (s)% ⊦ ~ i = j ↔ i + j = 0; (s)% ⊦ abs(i) + i = 0 ↔ i ≤ 0; (s)% ⊦ i ≤ j ↔ ¬ j < i; (ss)%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2% ⊦ ~ i < j ↔ 0 < j + i; (s)% ⊦ i < j ↔ ¬ j ≤ i; (ss)% ⊦ i < j → (j ≤ i ↔ false); (as) Used formulas: abs(i0 + i) = abs(i0) - abs(i)