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Proof step 3 from proof square-neq-pos (previous step)

j * j = i * j0 * j0, 0 < j, prime(i), 0 ≤ j0 ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ prime(i) ∧ gcd(j, j0) = 1 ∧ 0 < j ∧ 0 ≤ j0 → j * j ≠ i * j0 * j0
Proof step 5:
j * j = i * j0 * j0, 0 < j, prime(i), 0 ≤ j0 ⊦ prime(i) ∧ gcd(j, j0) = 1 ∧ 0 < j ∧ 0 ≤ j0

Rule argument

spec: <toplevel> name: square-neq-pos-h seq: ⊦ prime(i) ∧ gcd(j, j0) = 1 ∧ 0 < j ∧ 0 ≤ j0 → j * j ≠ i * j0 * j0 subst: [j0, i, j] → [j0, i, j] flags: <all paths>

Additional information

Used terms: j0, i, j