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Proof step 5 from proof square-neq-pos (previous step)

j * j = i * j0 * j0, 0 < j, prime(i), 0 ≤ j0 ⊦ prime(i) ∧ gcd(j, j0) = 1 ∧ 0 < j ∧ 0 ≤ j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
j * j = i * j0 * j0, 0 < j, prime(i), 0 ≤ j0 ⊦ gcd(j, j0) = 1

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j; (s)