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Proof step 7 from proof max-a (previous step)

⊦ i = max(max(i, j), j0), i < max(j, j0)

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 8:
⊦ i = max(max(i, j), j0), i < max(j, j0), max(i, j) < j0

Rule argument

fma: max(i, j) < j0

Additional information

Used simplifier rules: Max-right: ⊦ j < i → max(j, i) = i;%max-01: ⊦ max(i, j) < j0 ↔ i < j0 ∧ j < j0;% ⊦ ¬ i < j → (i = j ↔ ¬ j < i); (ss)% ⊦ i < j → ¬ j < i; (s) Used formulas: max(i, j) < j0