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Proof step 8 from proof max-a (previous step)

⊦ i = max(max(i, j), j0), i < max(j, j0), max(i, j) < j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
⊦ i = max(i, j), max(i, j) < j0, i < max(j, j0)

Rule argument

Additional information

Used simplifier rules: Max-left: ⊦ ¬ j < i → max(j, i) = j;