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Proof step 9 from proof max-a (previous step)

⊦ i = max(i, j), max(i, j) < j0, i < max(j, j0)

Heuristic weak cut applied rule cut formula

And closed the goal!

Rule argument

fma: i < j

Additional information

Used simplifier rules: Max-right: ⊦ j < i → max(j, i) = i;%Max-left: ⊦ ¬ j < i → max(j, i) = j;%Max-left: ⊦ ¬ j < i → max(j, i) = j;% ⊦ ¬ i < j → (i = j ↔ ¬ j < i); (ss)% ⊦ i < j → ¬ j < i; (s) Used formulas: i < j