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Proof step 10 from proof le-one (previous step)

1 < j, 1 < i * j, i < 0 ⊦ i = 0

User applied rule apply lemma

And obtained the following new goals

Proof step 11:
⊦ i < 0 → (0 < i * j ↔ j < 0)
Proof step 12:
i < 0, 1 < i * j, 1 < j, i < 0 → (0 < i * j ↔ j < 0) ⊦ i = 0

Rule argument

spec: <toplevel> name: zero-gr-01 seq: ⊦ i < 0 → (0 < i * j ↔ j < 0) subst: [i, j] → [i, j]

Additional information

Used terms: i, j