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Proof step 12 from proof le-one (
previous step
)
i < 0, 1 < i * j, 1 < j, i < 0 → (0 < i * j ↔ j < 0) ⊦ i = 0
User applied rule case distinction
And obtained the following new goals
Proof step 13
:
0 < i * j ↔ j < 0, 1 < j, 1 < i * j, i < 0 ⊦ i = 0
Rule argument
pos: left 4
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