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Proof step 13 from proof le-one (previous step)

0 < i * j ↔ j < 0, 1 < j, 1 < i * j, i < 0 ⊦ i = 0

User applied rule case distinction

And obtained the following new goals

Proof step 14:
i < 0, 1 < i * j, 1 < j ⊦ i = 0, j < 0, 0 < i * j

Rule argument

pos: left 1

Additional information

Used simplifier rules: zero-gr-01: ⊦ i < 0 → (0 < i * j ↔ j < 0);%associativity: ⊦ i * j * j0 = (i * j) * j0;%commutativity: ⊦ i * j = j * i;%lf-01: ⊦ i < j ∧ j < i0 → i +1 < i0; (forward) from specification int-basic1