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Proof step 2 from proof mods-ls-01 (previous step)

i < i0, abs(j0) < j ⊦ i * j < i0 * j + j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
abs(j0) < j, i < i0, i0 * j + j0 ≤ i * j ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ↔ ¬ j ≤ i; (ss)