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Proof step 3 from proof mods-ls-01 (previous step)

abs(j0) < j, i < i0, i0 * j + j0 ≤ i * j ⊦

User applied rule apply lemma

And obtained the following new goals

Proof step 4:
j * i + j0 ≤ j * i0, abs(j0) < j ⊦ i ≤ i0

Rule argument

spec: <toplevel> name: modlep-02 seq: j * i + j0 ≤ j * i0, abs(j0) < j ⊦ i ≤ i0 subst: [j, i, j0, i0] → [j, i0, j0, i]

Additional information

Used simplifier rules: commutativity: ⊦ i * j = j * i;% ⊦ i < j → (j ≤ i ↔ false); (as) Used terms: j, i0, j0, i