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Proof step 10 from proof numls-07 (previous step)

0 < (1 - i1) * j, j ≤ 0, j ≤ i1 * j ⊦

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

spec: int-abs name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [1, i1, i]

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: 1, i1, i