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Proof step 11 from proof numls-07 (previous step)

1 = i0 + i1, 0 < i0 * j, j ≤ i1 * j, j ≤ 0 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
1 = i0 + i1, i0 < 0, j < 0, i1 ≤ 1 ⊦ j = 0

Rule argument

Additional information

Used simplifier rules: zero-gr-03: ⊦ i ≤ 0 → (0 < i * j ↔ j < 0 ∧ i ≠ 0);%associativity: ⊦ i * j * j0 = (i * j) * j0;%commutativity: ⊦ i * j = j * i;%le-same-03: ⊦ i < 0 → (i ≤ i * j ↔ j ≤ 1);%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs% ⊦ i ≠ j → (i ≤ j ↔ i < j); (s)