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Proof step 12 from proof numls-07 (previous step)

1 = i0 + i1, i0 < 0, j < 0, i1 ≤ 1 ⊦ j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: int-abs name: le-def seq: ⊦ i ≤ j ↔ ¬ j < i subst: [j, i] → [1, i1] flags: <all paths>

Additional information

Used simplifier rules: ⊦ j < 0 ∧ ¬ i0 < i → i0 ≠ i + j; (s)%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2 Used terms: 1, i1