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Proof step 16 from proof three (previous step)

i * j = 3, 0 < i, 1 < i, 1 < j, i < 3, 0 < j ⊦ i = 3, 3 * 1 + 0 = j * i + 0 ∧ 0 ≤ 0 ∧ 0 ≤ 0 ∧ 0 ≤ 1 ∧ 1 ≤ i ∧ 0 ≤ 3 ∧ 3 < j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: commutativity: ⊦ i * j = j * i;%forward-le: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward) from specification int-abs% ⊦ i < j ↔ ¬ j ≤ i; (ss)% ⊦ 1 ≤ i ↔ 0 < i; (s)% ⊦ i + 0 = i; (s)%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2