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Proof step 17 from proof three (previous step)

i * j = 3, 0 < j, i < 3, 1 < j, 1 < i, 0 < i, j ≤ 3 ⊦ i = 3

User applied rule cut formula

And obtained the following new goals

Proof step 18:
i * j = 3, 0 < i, 1 < i, 1 < j, i < 3, 0 < j, j ≤ 3 ⊦ i = 3, j = 3

Rule argument

fma: j = 3

Additional information

Used simplifier rules: eq-same-02: ⊦ 0 < i → (i * j = i ↔ j = 1);%associativity: ⊦ i * j * j0 = (i * j) * j0;%commutativity: ⊦ i * j = j * i; Used formulas: j = 3