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Proof step 18 from proof three (previous step)

i * j = 3, 0 < i, 1 < i, 1 < j, i < 3, 0 < j, j ≤ 3 ⊦ i = 3, j = 3

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
i * j = 3, 0 < j, i < 3, 1 < j, 1 < i, 0 < i, j < 3 ⊦ i = 3, j = 3

Rule argument

Additional information

Used simplifier rules: ⊦ i ≠ j → (i ≤ j ↔ i < j); (s)