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Proof step 19 from proof three (previous step)

i * j = 3, 0 < j, i < 3, 1 < j, 1 < i, 0 < i, j < 3 ⊦ i = 3, j = 3

User applied rule cut formula

And obtained the following new goals

Proof step 20:
i * j = 3, j = 2, j < 3, 0 < i, 1 < i, 1 < j, i < 3, 0 < j ⊦ i = 3, j = 3
Proof step 23:
i * j = 3, j < 3, 0 < i, 1 < i, 1 < j, i < 3, 0 < j ⊦ i = 3, j = 3, j = 2

Rule argument

fma: j = 2

Additional information

Used formulas: j = 2