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Proof step 6 from proof div2-2pot (previous step)

0 < 2 ^ i, 0 ≤ i, 0 ≤ j ⊦ 2 ^ i * 2 = 2 ^ (i + 1), j / (2 ^ i * 2) = j / 2 ^ (i + 1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ 0 < i → j ^ i = j ^ i -1 * j
Proof step 8:
0 < 2 ^ i, 0 < i + 1, 0 ≤ j, 0 ≤ i ⊦ 2 ^ i * 2 = 2 ^ (i + 1)-1 * 2, j / (2 ^ i * 2) = j / (2 ^ (i + 1)-1 * 2)

Rule argument

spec: <toplevel> name: Pot-pos seq: ⊦ 0 < i → j ^ i = j ^ i -1 * j subst: [i, j] → [i + 1, 2] flags: <all paths>

Additional information

Used simplifier rules: ⊦ i < j + 1 ↔ i ≤ j; (s)% ⊦ i ≤ j ↔ ¬ j < i; (ss)% ⊦ i ≤ j → (j < i ↔ false); (as)%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2 Used terms: i + 1, 2