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Proof step 8 from proof div2-2pot (previous step)

0 < 2 ^ i, 0 < i + 1, 0 ≤ j, 0 ≤ i ⊦ 2 ^ i * 2 = 2 ^ (i + 1)-1 * 2, j / (2 ^ i * 2) = j / (2 ^ (i + 1)-1 * 2)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2% ⊦ (i + 1)-1 = i; (s)